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Codeforces_327_C
http://codeforces.com/problemset/problem/327/C
等比求和相加,有mod的出现,所以要算逆元。
#include<iostream>#include<cstring>#include<cstdio>#include<algorithm>#define LL long long#define MOD 1000000007using namespace std;char s[100005];int k;LL p_mod(LL a,LL b,LL c){ LL ans = 1; a = a%c; while(b > 0) { if(b%2 == 1) ans = (ans*a)%c; b /= 2; a = (a*a)%c; } return ans;}LL get_inv(LL a,LL c){ return p_mod(a,c-2,c);}int main(){ scanf("%s%d",s,&k); LL ans = 0; int len = strlen(s); LL x = p_mod(2,len,MOD); LL y = get_inv(x-1,MOD); x = p_mod(x,k,MOD)-1; LL z = 0; for(int i = 0;i < len;i++) { if(s[i] == ‘0‘ || s[i] == ‘5‘) { z = (z+p_mod(2,i,MOD))%MOD; } } ans = (((z*x)%MOD*y)%MOD)%MOD; printf("%I64d\n",ans); return 0;}
Codeforces_327_C
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