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hdu 1396 Counting Triangles (递推)
Counting Triangles
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2012 Accepted Submission(s): 966
Problem Description
Given an equilateral triangle with n the length of its side, program to count how many triangles in it.
Input
The length n (n <= 500) of the equilateral triangle‘s side, one per line.
process to the end of the file
process to the end of the file
Output
The number of triangles in the equilateral triangle, one per line.
Sample Input
1 2 3
Sample Output
1 5 13
Author
JIANG, Jiefeng
Source
ZOJ Monthly, June 2003
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推了一段时间没推出来= =!
1 //15MS 232K 347 B C++ 2 /* 3 4 递推: 5 a[n] = a[n-1] + n * (n + 1) / 2; 6 7 还有一种情况是最底下一行顶角朝下的三角形: 8 观察规律得:left = (n-1) + (n-1)-2 + (n-1)-4... + last(n为奇数, last为2, 反之为1) 9 10 a[n] = a[n] + left; 11 12 13 */ 14 #include<stdio.h> 15 int main(void) 16 { 17 __int64 ans[505]={0,1}; 18 for(int i=2;i<=500;i++){ 19 ans[i]=ans[i-1]+i*(i+1)/2; 20 int k=i-1; 21 while(k>0){ 22 ans[i]+=k; 23 k-=2; 24 } 25 } 26 int n; 27 while(scanf("%d",&n)!=EOF) 28 { 29 printf("%I64d\n",ans[n]); 30 } 31 return 0; 32 }
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