最长单调递增子序列问题

题目：设计一个 O（ n ^ 2 ）复杂度的算法，找出由 n 个数组成的序列的最长单调递增子序列。

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);

		while (scanner.hasNext()) {
			int n = scanner.nextInt();

			int[] nums = new int[n + 1];// 数列数据
			int[] sub_len = new int[n + 1];// sub_len[i]表示从i到n的最长递增序列的长度
			int[] sub_index = new int[n + 1];// sub_index[i]表示第i个数据的后面一个数据的下标

			for (int i = 1; i <= n; i++) {
				nums[i] = scanner.nextInt();
				sub_len[i] = 1;
				sub_index[i] = 0;
			}

			for (int i = n - 1; i >= 1; i--) {
				int max = 0, p = 0;// 临时变量
				for (int j = i + 1; j <= n; j++) {
					if (nums[i] < nums[j] && sub_len[j] > max) {
						max = sub_len[j];
						p = j;
					}

					if (p != 0) {
						sub_len[i] = sub_len[p] + 1;
						sub_index[i] = p;
					}
				}
			}

			int max = 0, p = 0;
			for (int i = 1; i <= n; i++) {
				if (sub_len[i] > max) {
					max = sub_len[i];
					p = i;
				}
			}
			System.out.println("最长长度：" + max);

			System.out.print("最长递增序列：");
			while (p != 0) {
				System.out.print(nums[p] + " ");
				p = sub_index[p];
			}
			System.out.println();
		}
		scanner.close();
	}
}