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LeetCode-Unique Word Abbreviation
An abbreviation of a word follows the form <first letter><number><last letter>. Below are some examples of word abbreviations:
a) it --> it (no abbreviation) 1b) d|o|g --> d1g 1 1 1 1---5----0----5--8c) i|nternationalizatio|n --> i18n 1 1---5----0d) l|ocalizatio|n --> l10n
Assume you have a dictionary and given a word, find whether its abbreviation is unique in the dictionary. A word‘s abbreviation is unique if no other word from the dictionary has the same abbreviation.
Example:
Given dictionary = [ "deer", "door", "cake", "card" ]isUnique("dear") -> falseisUnique("cart") -> trueisUnique("cane") -> falseisUnique("make") -> true
Solution:1 public class ValidWordAbbr { 2 Map<String, String> abbrMap; 3 4 public ValidWordAbbr(String[] dictionary) { 5 abbrMap = new HashMap<String, String>(); 6 7 for (String word : dictionary) { 8 String abbr = getAbbr(word); 9 // the abbr is invalid, if it exsits and the corresponding word is not current word.10 if (abbrMap.containsKey(abbr) && !abbrMap.get(abbr).equals(word)) {11 abbrMap.put(abbr, "");12 } else {13 abbrMap.put(abbr, word);14 }15 }16 }17 18 public boolean isUnique(String word) {19 String abbr = getAbbr(word);20 // true, if @abbr does not exsit or the corresponding word is the @word.21 return (!abbrMap.containsKey(abbr)) || (abbrMap.containsKey(abbr) && abbrMap.get(abbr).equals(word));22 }23 24 public String getAbbr(String word){25 if (word.length()<=2) return word;26 27 StringBuilder builder = new StringBuilder();28 builder.append(word.charAt(0));29 builder.append(word.length()-2);30 builder.append(word.charAt(word.length()-1));31 32 return builder.toString();33 }34 }35 36 // Your ValidWordAbbr object will be instantiated and called as such:37 // ValidWordAbbr vwa = new ValidWordAbbr(dictionary);38 // vwa.isUnique("Word");39 // vwa.isUnique("anotherWord");
LeetCode-Unique Word Abbreviation
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