题意：

给定n长的数组，m个操作

下面是每个点的颜色

下面m个操纵：

1 l r col 染色

2 l r col 询问区间内为col颜色的点数

== 就是普通的操作+区间内最大最小颜色数的优化，感觉很不科学。。。

==感觉可以卡掉这种写法。。反正就是不科学嘛 

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <vector>
using namespace std;
#define L(x) tree[x].l
#define R(x) tree[x].r
#define Len(x) tree[x].len
#define Lazy(x) tree[x].lazy
#define M(x) tree[x].minn
#define W(x) tree[x].maxx
#define Lson(x) (x<<1)
#define Rson(x) (x<<1|1)
const int N = 100010;
struct node{
	int l, r, len, lazy, minn, maxx;
}tree[N<<2];
int col[N];
void push_up(int id){
	if(Lazy(Lson(id)) == Lazy(Rson(id)))
		Lazy(id) = Lazy(Lson(id));
	else Lazy(id) = -1;
	M(id) = min(M(Lson(id)), M(Rson(id)));
	W(id) = max(W(Lson(id)), W(Rson(id)));
}
void push_down(int id){
	if(Lazy(id) != -1){
		Lazy(Lson(id)) = Lazy(Rson(id)) = Lazy(id);
		M(Lson(id)) = W(Lson(id)) = Lazy(id);
		M(Rson(id)) = W(Rson(id)) = Lazy(id);
	}
}
void build(int l, int r, int id){
	L(id) = l; R(id) = r;
	Len(id) = r-l+1;
	Lazy(id) = -1;
	if(l == r){
		Lazy(id) = col[l];
		W(id) = M(id) = col[l];
		return ;
	}
	int mid = (l+r)>>1;
	build(l, mid, Lson(id));
	build(mid+1, r, Rson(id));
	push_up(id);
}
void updata(int l, int r,int val, int id){
	if(l == L(id) && R(id) == r){
		Lazy(id) = val;
		W(id) = M(id) = val;
		return ;
	}
	push_down(id);
	int mid = (L(id) + R(id)) >>1;
	if(mid < l)
		updata(l, r, val, Rson(id));
	else if(r <= mid)
		updata(l, r, val, Lson(id));
	else {
		updata(l, mid, val, Lson(id));
		updata(mid+1, r, val, Rson(id));
	}
	push_up(id);
}
int query(int l, int r, int col, int id){
	if(!(M(id)<=col && col<=W(id))) return 0;
	if(Lazy(id)!=-1){
		if(Lazy(id) == col)
			return r-l+1;
		else return 0;
	}
	push_down(id);
	int mid = (L(id) + R(id)) >>1;
	if(mid < l)
		return query(l, r, col, Rson(id));
	else if(r <= mid)
		return query(l, r, col, Lson(id));
	else
		return query(l, mid, col, Lson(id)) + query(mid+1, r, col, Rson(id));
}
int n, que;

int main() {
	while (cin>>n>>que) {
		for(int i = 1; i <= n; i++)scanf("%d", &col[i]);
		build(1, n, 1);
		while(que--){
			int type, l, r, color;
			scanf("%d %d %d %d", &type, &l, &r, &color);
			l++; r++;
			if(type == 1)
				updata(l, r, color, 1);
			else
				printf("%d\n", query(l, r, color, 1));

		}
	}
	return 0;
}
/*
5 12
1 2 3 4 0
2 1 3 3
1 1 3 1
2 1 3 3
2 0 3 1
2 3 4 1
1 0 4 0
2 0 4 0
2 0 4 2000000000
1 0 0 1
1 4 4 2
2 0 4 1
2 0 4 2

*/

HDU 4391 Paint The Wall 线段树（水