首页 > 代码库 > Container With Most Water

Container With Most Water

Given n non-negative integers a1, a2, ...,an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of linei is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

答案

public class Solution {
    public int maxArea(int[] height) {
        if(height==null||height.length<2)
        {
            return 0;
        }
        int N=height.length;
        int []left=new int[N];
        int []right=new int[N];
        int max=0;
        List<Integer> listLeft=new LinkedList<Integer>();
        List<Integer> listRight=new LinkedList<Integer>();
        left[0]=height[0];
        right[N-1]=height[N-1];
        listLeft.add(0);
        listRight.add(N-1);
        for(int i=1;i<N;i++)
        {
            if(height[i]>left[i-1])
            {
                left[i]=height[i];
                listLeft.add(i);
            }
            else
            {
                left[i]=left[i-1];
            }
        }
        for(int i=N-2;i>=0;i--)
        {
            if(height[i]>right[i+1])
            {
                right[i]=height[i];
                listRight.add(i);
            }
            else
            {
                right[i]=right[i+1];
            }
        }
        for(Integer i:listLeft)
        {
            for(Integer j:listRight)
            {
                if(j<=i)
                {
                    break;
                }
                max=Math.max(max,(j-i)*Math.min(height[i],height[j]));
            }
        }
        return max;
    }
}


Container With Most Water