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动态构造结构体数组

动态构造结构体数组

 

# include <stdio.h># include <malloc.h>struct Student{    int age;    float score;    char name[100];};int main(void){    int len;    struct Student * pArr;    int i, j;    struct Student t;        //动态的构造一维数组    printf("请输入学生的个数:\n");    printf("len = ");    scanf("%d", &len);    pArr = (struct Student *)malloc(len * sizeof(struct Student));        //输入    for (i=0; i<len; ++i)    {        printf("请输入第%d个学生的信息:\n", i+1);        printf("age = ");        scanf("%d", &pArr[i].age);        printf("name = ");        scanf("%s", pArr[i].name);  //name是数组名,本身就已经是数组首元素的地址, 所以pArr[i].name 不能改成 &pArr[i].name        printf("score = ");        scanf("%f", &pArr[i].score);    }    //按学生成绩升序排序 冒泡算法    for (i=0; i<len-1; ++i)    {        for (j=0; j<len-1-i; ++j)        {            if (pArr[j].score > pArr[j+1].score) //>升序 <降序            {                t = pArr[j];                pArr[j] = pArr[j+1];                pArr[j+1] = t;            }        }    }    printf("\n\n学生的信息是:\n");    //输出    for (i=0; i<len; ++i)    {        printf("第%d个学生的信息是:\n", i+1);        printf("age = %d\n", pArr[i].age);        printf("name = %s\n", pArr[i].name);  //name是数组名,本身就已经是数组首元素的地址, 所以pArr[i].name 不能改成 &pArr[i].name        printf("score = %f\n", pArr[i].score);            printf("\n");    }    return 0;}