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2440裸机串口调试 while(!(rUTRSTAT0 & 0x2));问题

前两天写RTC中断 使用串口输出

发现程序会出现while(!(rUTRSTAT0 & 0x2));出不来的情况,但是中断是正常运作的

解决方法:

 main函数增加:

        U32 mpll_val = 0,consoleNum;
        Port_Init();   //定义在2440lib.c
        mpll_val = (92<<12)|(1<<4)|(1);                                                                                                                    
	//init FCLK=400M,
	ChangeMPllValue((mpll_val>>12)&0xff, (mpll_val>>4)&0x3f, mpll_val&3);    (定义在2440lib.c)
	ChangeClockDivider(14, 12);   //the result of rCLKDIVN [0:1:0:1] 3-0 bit  (定义在2440lib.c)
	cal_cpu_bus_clk();            //HCLK=100M   PCLK=50M
   
        consoleNum = 0;	              // Uart 1 select for debug.
	Uart_Init( 0,115200 );        // 定义在2440lib.c      
	Uart_Select( consoleNum );    // 定义在2440lib.c

cal_cpu_bus_clk()定义如下:

static U32 UPLL;
static U32 cpu_freq;
void cal_cpu_bus_clk(void)
{
	U32 val;
	U8 m, p, s;
	
	val = rMPLLCON;
	m = (val>>12)&0xff;
	p = (val>>4)&0x3f;
	s = val&3;

	//(m+8)*FIN*2 不要超出32位数!
	FCLK = ((m+8)*(FIN/100)*2)/((p+2)*(1<<s))*100;
	
	val = rCLKDIVN;
	m = (val>>1)&3;
	p = val&1;	
	val = rCAMDIVN;
	s = val>>8;
	
	switch (m) {
	case 0:
		HCLK = FCLK;
		break;
	case 1:
		HCLK = FCLK>>1;
		break;
	case 2:
		if(s&2)
			HCLK = FCLK>>3;
		else
			HCLK = FCLK>>2;
		break;
	case 3:
		if(s&1)
			HCLK = FCLK/6;
		else
			HCLK = FCLK/3;
		break;
	}
	
	if(p)
		PCLK = HCLK>>1;
	else
		PCLK = HCLK;
	
	if(s&0x10)
		cpu_freq = HCLK;
	else
		cpu_freq = FCLK;
		
	val = rUPLLCON;
	m = (val>>12)&0xff;
	p = (val>>4)&0x3f;
	s = val&3;
	UPLL = ((m+8)*FIN)/((p+2)*(1<<s));
	UCLK = (rCLKDIVN&8)?(UPLL>>1):UPLL;
}