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hdu 5890 Eighty seven 暴力+bitset优化背包

2024-08-13 16:53:11   222人阅读

Eighty seven

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 102400/102400 K (Java/Others)


Problem Description
Mr. Fib is a mathematics teacher of a primary school. In the next lesson, he is planning to teach children how to add numbers up. Before the class, he will prepare Ncards with numbers. The number on the i-th card is ai. In class, each turn he will remove no more than 3 cards and let students choose any ten cards, the sum of the numbers on which is 87. After each turn the removed cards will be put back to their position. Now, he wants to know if there is at least one solution of each turn. Can you help him?
 

 

Input
The first line of input contains an integer t (t≤5), the number of test cases. t test cases follow.
For each test case, the first line consists an integer N(N≤50).
The second line contains N non-negative integers a1,a2,...,aN. The i-th number represents the number on the i-th card. The third line consists an integer Q(Q≤100000). Each line of the next Q lines contains three integers i,j,k, representing Mr.Fib will remove the i-th, j-th, and k-th cards in this turn. A question may degenerate while i=j, i=k or j=k.
 

 

Output
For each turn of each case, output ‘Yes‘ if there exists at least one solution, otherwise output ‘No‘.
 

 

Sample Input
1121 2 3 4 5 6 7 8 9 42 21 22101 2 33 4 52 3 210 10 1010 11 1110 1 11 2 101 11 121 10 1011 11 12
 

 

Sample Output
NoNoNoYesNoYesNoNoYesYes
 

 

Source
2016 ACM/ICPC Asia Regional Qingdao Online
技术分享

bitset把87*n优化成10*n；

#include<bits/stdc++.h>using namespace std;#define ll long long#define pi (4*atan(1.0))const int N=1e5+10,M=1e6+10,inf=1e9+10,mod=1e9+7;const ll INF=1e18+10;bitset<90>dp[11];int ans[60][60][60];int a[100],n,m;int q[5];int check(int x,int y,int z){    for(int i=0;i<=n;i++)dp[i].reset();    dp[0][0]=1;    for(int i=1;i<=n;i++)    {        if(i!=x&&i!=y&&i!=z)            for(int t=10;t>=1;t--)                dp[t]|=dp[t-1]<<a[i];    }    if(dp[10][87]==1)        return 1;        return 0;}int main(){    int T;    scanf("%d",&T);    while(T--)    {        memset(ans,0,sizeof(ans));        scanf("%d",&n);        for(int i=1;i<=n;i++)            scanf("%d",&a[i]);        for(int i=1;i<=n;i++)            for(int j=i;j<=n;j++)                for(int k=j;k<=n;k++)                if(check(i,j,k))ans[i][j][k]=1;        scanf("%d",&m);        while(m--)        {            for(int i=0;i<3;i++)                scanf("%d",&q[i]);            sort(q,q+3);            if(ans[q[0]][q[1]][q[2]])                printf("Yes\n");            else                printf("No\n");        }    }    return 0;}

 

hdu 5890 Eighty seven 暴力+bitset优化背包


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