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Combination Sum
Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set 2,3,6,7
and target 7
,
A solution set is: [7]
[2, 2, 3]
class Solution {
public:
vector<vector<int> > combinationSum(vector<int> &candidates, int target)
{
//sort candidates
int size=candidates.size();
for(int i=0;i<size;i++)
for(int j=i+1;j<size;j++)
if(candidates[i]>candidates[j])
{
int tmp=candidates[i];
candidates[i]=candidates[j];
candidates[j]=tmp;
}
//dfs
vector<vector<int>> result;
if(size==0) return result;
int v[target/candidates[0]];
int cdep=0;
int vdep=0;
dfs(result,candidates,size,v,cdep,vdep,target);
return result;
}
void dfs(vector<vector<int>>& result,vector<int> &candidates,int& csize,int* v,int& cdep,int& vdep,int& target)
{
if(target==0)
{
vector<int> vals;
for(int i=0;i<vdep;i++)
vals.push_back(v[i]);
result.push_back(vals);
return;
}
if(cdep==csize || target<candidates[cdep]) return;
int dup=target/candidates[cdep];
for(int i=0;i<=dup;i++)
{
//add to v
for(int j=0;j<i;j++) v[vdep+j]=candidates[cdep];
//search next candidate
target=target-i*candidates[cdep];
cdep=cdep+1;
vdep=vdep+i;
dfs(result,candidates,csize,v,cdep,vdep,target);
vdep=vdep-i;
cdep=cdep-1;
target=target+i*candidates[cdep];
}
}
};
public:
vector<vector<int> > combinationSum(vector<int> &candidates, int target)
{
//sort candidates
int size=candidates.size();
for(int i=0;i<size;i++)
for(int j=i+1;j<size;j++)
if(candidates[i]>candidates[j])
{
int tmp=candidates[i];
candidates[i]=candidates[j];
candidates[j]=tmp;
}
//dfs
vector<vector<int>> result;
if(size==0) return result;
int v[target/candidates[0]];
int cdep=0;
int vdep=0;
dfs(result,candidates,size,v,cdep,vdep,target);
return result;
}
void dfs(vector<vector<int>>& result,vector<int> &candidates,int& csize,int* v,int& cdep,int& vdep,int& target)
{
if(target==0)
{
vector<int> vals;
for(int i=0;i<vdep;i++)
vals.push_back(v[i]);
result.push_back(vals);
return;
}
if(cdep==csize || target<candidates[cdep]) return;
int dup=target/candidates[cdep];
for(int i=0;i<=dup;i++)
{
//add to v
for(int j=0;j<i;j++) v[vdep+j]=candidates[cdep];
//search next candidate
target=target-i*candidates[cdep];
cdep=cdep+1;
vdep=vdep+i;
dfs(result,candidates,csize,v,cdep,vdep,target);
vdep=vdep-i;
cdep=cdep-1;
target=target+i*candidates[cdep];
}
}
};
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