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64. Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
1 class Solution { 2 public: 3 int minPathSum(vector<vector<int>>& grid) { 4 if(grid.size() == 0 || grid[0].size() == 0){ 5 return 0; 6 } 7 8 int row = grid.size(); 9 int col = grid[0].size();10 11 int dp[row][col];12 13 dp[0][0] = grid[0][0];14 15 for(int i = 1; i < row; i++){16 dp[i][0] = dp[i-1][0] + grid[i][0];17 }18 19 for(int j = 1; j < col; j++){20 dp[0][j] = dp[0][j-1] + grid[0][j];21 }22 23 for(int i = 1; i < row; i++){24 for(int j =1; j < col; j++){25 dp[i][j] = min(dp[i-1][j] , dp[i][j-1]) + grid[i][j];26 }27 }28 return dp[row-1][col-1];29 }30 };
64. Minimum Path Sum
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