首页 > 代码库 > 64. Minimum Path Sum
64. Minimum Path Sum
题目:
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
Hide Tags
Array Dynamic Programming链接: http://leetcode.com/problems/minimum-path-sum/
5/20/2017
注意第7,9,12行
1 public class Solution { 2 public int minPathSum(int[][] grid) { 3 if (grid == null || grid.length == 0 || grid[0].length == 0) { 4 return 0; 5 } 6 int[] path = new int[grid[0].length]; 7 path[0] = grid[0][0]; 8 for (int i = 1; i < grid[0].length; i++) { 9 path[i] = grid[0][i] + path[i - 1]; 10 } 11 for (int i = 1; i < grid.length; i++) { 12 path[0] = path[0] + grid[i][0]; 13 for (int j = 1; j < grid[i].length; j++) { 14 path[j] = Math.min(path[j - 1], path[j]) + grid[i][j]; 15 } 16 } 17 return path[grid[0].length - 1]; 18 } 19 }
64. Minimum Path Sum
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。