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001. 3和5的倍数

Problem 1: Multiples of 3 and 5

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.


意思就是让你算出在1000以下的3或者5的倍数之和。

我的python代码:

print sum(x for x in range(1000) if x%3==0 or x%5==0)

很简单!