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sqlserver 同字段值拼接 列转行
sqlserver 同字段值拼接(效果同oracle中的wm_concat)
2012-08-13 18:20:46| 分类: sqlserver | 标签:sqlserver |举报 |字号大中小 订阅
合并列值
--*******************************************************************************************
表结构,数据如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即:group by id, 求 value 的和(字符串相加)
1. 旧的解决方法(在sql server 2000中只能用函数解决。)
--=============================================================================
create table tb(id int, value varchar(10))
insert into tb values(1, ‘aa‘)
insert into tb values(1, ‘bb‘)
insert into tb values(2, ‘aaa‘)
insert into tb values(2, ‘bbb‘)
insert into tb values(2, ‘ccc‘)
go
--1. 创建处理函数
CREATE FUNCTION dbo.f_strUnite(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @str varchar(8000)
SET @str = ‘‘
SELECT @str = @str + ‘,‘ + value FROM tb WHERE id=@id
RETURN STUFF(@str, 1, 1, ‘‘)
END
GO
-- 调用函数
SELECt id, value = http://www.mamicode.com/dbo.f_strUnite(id) FROM tb GROUP BY id
drop table tb
drop function dbo.f_strUnite
go
/*
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(所影响的行数为 2 行)
*/
--===================================================================================
2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。)
create table tb(id int, value varchar(10))
insert into tb values(1, ‘aa‘)
insert into tb values(1, ‘bb‘)
insert into tb values(2, ‘aaa‘)
insert into tb values(2, ‘bbb‘)
insert into tb values(2, ‘ccc‘)
go
-- 查询处理
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY(
SELECT [values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM tb N
WHERE id = A.id
FOR XML AUTO
), ‘ <N value="http://www.mamicode.com/‘, ‘,‘), ‘"/>‘, ‘‘), 1, 1, ‘‘)
)N
drop table tb
/*
id values
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
(2 行受影响)
*/
--SQL2005中的方法2
create table tb(id int, value varchar(10))
insert into tb values(1, ‘aa‘)
insert into tb values(1, ‘bb‘)
insert into tb values(2, ‘aaa‘)
insert into tb values(2, ‘bbb‘)
insert into tb values(2, ‘ccc‘)
go
select id, [values]=stuff((select ‘,‘+[value] from tb t where id=tb.id for xml path(‘‘)), 1, 1, ‘‘)
from tb
group by id
/*
id values
----------- --------------------
1 aa,bb
2 aaa,bbb,ccc
(2 row(s) affected)
*/
drop table tb
来源:http://topic.csdn.net/u/20090924/11/9a920a29-a6a2-428f-9fab-577058304898.html
自己仿着写了一个例子
select b.SystemName 系统, m.Name 一级菜单,m1.Name 二级菜单,f.Name 按钮,m1.ID
into #temp
from Menu m
inner join Menu m1 on m.ID=m1.ParentID
left join functions f on m1.ID=f.MenuID
inner join BaseSystem b on b.SystemFlag=m.SystemFlag
where b.SystemFlag not in(‘EP‘,‘MD‘,‘PC‘) order by m.SystemFlag ,m.OrderNo
SELECT B.系统,B.一级菜单, B.二级菜单,StuList 按钮 FROM (
SELECT 二级菜单,系统,一级菜单,
(SELECT 按钮+‘,‘ FROM #temp
WHERE 二级菜单=A.二级菜单
FOR XML PATH(‘‘)) AS StuList
FROM #temp A
GROUP BY 系统,一级菜单,二级菜单
) B