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判断二叉树是否平衡

 

 

 

//                      1//              2             3//        4                         5////class Solution {public:    int maxDepth(TreeNode* root){        if(root==NULL)            return 0;         return 1+max(maxDepth(root->left),maxDepth(root->right));    }    bool danbian(TreeNode *root)        {        if(root==NULL)            return 1;        if(root->left!=NULL && root->right!=NULL)            return 0;        if(root->left==NULL)            ;//danbian(root->right);        if(root->right==NULL)            ;//danbian(root->left);        return 1;    }    int minDepth(TreeNode* root){                if(root==NULL)            return 0;                 if(root->left == NULL) return minDepth(root->right) + 1;         if(root->right == NULL) return minDepth(root->left) + 1;        int leftDepth = minDepth(root->left);        int rightDepth = minDepth(root->right);        return leftDepth < rightDepth ? (leftDepth + 1) : (rightDepth + 1);    }    bool IsBalanced_Solution(TreeNode* pRoot) {        int max=maxDepth(pRoot);        int min=minDepth(pRoot);        if(danbian(pRoot))            min=1;        if(max-min>1)            return 0;        return 1;                    }};

  

判断二叉树是否平衡