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leetcode 160: Read N Characters Given Read4 II - Call multiple times
Total Accepted: 909 Total Submissions: 4757
The API: int read4(char *buf)
reads 4 characters at a time from a file.
The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.
By using the read4
API, implement the function int read(char *buf, int n)
that readsn characters from the file.
The read
function may be called multiple times.
[分析]
用一个cache 和 一个指针, 不够就read4
[CODE]
// Forward declaration of the read4 API. int read4(char *buf); class Solution { public: /** * @param buf Destination buffer * @param n Maximum number of characters to read * @return The number of characters read */ char cache[4]; int p = -1; int r = 0; int read(char *buf, int n) { if(n<=0) return 0; int s = n; if(p==-1) { r = read4(cache); p = 0; } while(n>0 && p<r) { *buf = cache[p]; ++buf; n--; p++; if(p==r) { r = read4(cache); p = 0; } } return s - n; } };
leetcode 160: Read N Characters Given Read4 II - Call multiple times
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