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LeetCode Convert Sorted List to Binary Search Tree
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
1 /** 2 * Definition for singly-linked list. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int x) { val = x; next = null; } 7 * } 8 */ 9 /**10 * Definition for binary tree11 * public class TreeNode {12 * int val;13 * TreeNode left;14 * TreeNode right;15 * TreeNode(int x) { val = x; }16 * }17 */18 public class Solution {19 public TreeNode sortedListToBST(ListNode head) {20 ArrayList<ListNode> listNodes=new ArrayList<ListNode>();21 if (head==null) return null;22 ListNode node=head;23 while (node!=null) {24 listNodes.add(node);25 node=node.next;26 }27 int middle=(listNodes.size()-1)/2;28 TreeNode root =new TreeNode(listNodes.get(middle).val);29 if (middle>0){30 listNodes.get(middle-1).next=null;31 root.left=sortedListToBST(listNodes.get(0));32 33 }34 if (middle<listNodes.size()-1){35 root.right=sortedListToBST(listNodes.get(middle+1));36 37 }38 return root;39 40 }41 }
LeetCode Convert Sorted List to Binary Search Tree
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