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ZigZag Conversion

2024-07-30 23:47:09   215人阅读

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   NA P L S I I GY   I   R

And then read line by line: "PAHNAPLSIIGYIR"

 

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

 

代码：z字形遍历二维数组。

class Solution {public:    string convert(string s, int nRows)     {         if(s.empty()||nRows==1) return s;         string res;          char a[1000][1000];         memset(a,0,sizeof(a));         int i=0,j=0,q=0;         int j_time=0;         int len=s.size();         while (i<nRows&&q<len){             a[i][j]=s[q];             ++i;++q;             if(i==nRows&&q<len){                 --i;                 j_time=0;                 while (j_time<(nRows-1)&&q<len){                     --i;                     ++j_time;                     ++j;                     a[i][j]=s[q];++q;                 }                 ++i;             }         }         for (int i=0;i<nRows;++i)         {             for (int j=0;j<len;++j)             {                 if(a[i][j]!=‘\0‘)                     res.push_back(a[i][j]);             }         }         return res;    }};

 

ZigZag Conversion


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