Binary String Matching

描述

Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit

输入

The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.

输出

For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.

样例输入

31110011101101011100100100100011010110100010101011 

样例输出

303 

 #include <iostream>#include <string>using namespace std;int main(){    int n;    cin>>n;    while(n--)    {        string strA;        string strB;        int count = 0;        cin>>strA;        cin>>strB;        int A = strA.size();        int B = strB.size();        for(int i=0; i<B; i++)        {            if(strB.substr(i, A) == strA)                count ++;        }        cout<<count<<endl;    }    return 0;}        

Binary String Matching