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Binary String Matching

2024-07-02 00:18:36   227人阅读

Binary String Matching

时间限制：3000 ms  |  内存限制：65535 KB
难度：3
 
描述
Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit
 
输入
The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.
输出
For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.
样例输入
3
11
1001110110
101
110010010010001
1010
110100010101011
样例输出
3
0
3

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#include<iostream>
#include<string>
using namespace std;
int main()
{
string s1,s2;
int n;
cin>>n;
while(n--)
{
cin>>s1>>s2;
unsigned int m=s2.find(s1,0);
int num=0;
while(m!=string::npos)
{
num++;
m=s2.find(s1,m+1);
}
cout<<num<<endl;
}
}

　　

 


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