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Binary String Matching
描述
Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit
- 输入
- The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.
- 输出
- For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.
- 样例输入
- 3
- 11
- 1001110110
- 101
- 110010010010001
- 1010
- 110100010101011
- 样例输出
- 3
- 0
- 3
1 #include <stdio.h> 2 #include <string.h> 3 4 int main(){ 5 int T; 6 char a[11]; 7 char temp[11]; 8 char b[1001]; 9 int a_length;10 int b_length;11 int i;12 int amount;13 14 scanf("%d",&T);15 16 while(T--){17 scanf("%s%s",a,b);18 a_length=strlen(a);19 b_length=strlen(b);20 21 amount=0;22 for(i=0;i<b_length-a_length+1;i++){23 memset(temp,0,11);24 strncpy(temp,&b[i],a_length);25 26 if(strcmp(temp,a)==0){27 amount++;28 }29 }30 printf("%d\n",amount);31 }32 return 0;33 }
Binary String Matching
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