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Wildcard Matching
Implement wildcard pattern matching with support for ‘?‘
and ‘*‘
.
‘?‘ Matches any single character. ‘*‘ Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial). The function prototype should be: bool isMatch(const char *s, const char *p) Some examples: isMatch("aa","a") → false isMatch("aa","aa") → true isMatch("aaa","aa") → false isMatch("aa", "*") → true isMatch("aa", "a*") → true isMatch("ab", "?*") → true isMatch("aab", "c*a*b") → false
答案
public class Solution { public boolean isMatch(String str, String pattern) { int sLen = str.length(); int pLen = pattern.length(); int i = 0; int j = 0; int pStr = -1; int pPattern = -1; while (i < sLen) { if (j < pLen && (pattern.charAt(j) == '?' || pattern.charAt(j) == str.charAt(i))) { i++ ; j++ ; } else if (j < pLen && pattern.charAt(j) == '*') { pStr = i; pPattern = j; j++ ; } else if (pPattern != -1) { pStr++ ; i = pStr; j = pPattern + 1; } else { return false; } } while (j < pLen && pattern.charAt(j) == '*') { j++ ; } return j == pLen; } }
Wildcard Matching
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