首页 > 代码库 > LeetCode Count and Say 解题报告
LeetCode Count and Say 解题报告
The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...
1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.
Given an integer n, generate the nth sequence.
Note: The sequence of integers will be represented as a string.
https://oj.leetcode.com/problems/count-and-say/
如何数(shu 三声) 数(shu 四声)
1,11,21,1211,111221,312211,13112221,1113213211
先上AC代码,
1, 11, 21, 1211, 111221, ...
1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.
Given an integer n, generate the nth sequence.
Note: The sequence of integers will be represented as a string.
https://oj.leetcode.com/problems/count-and-say/
如何数(shu 三声) 数(shu 四声)
1,11,21,1211,111221,312211,13112221,1113213211
先上AC代码,
public class Solution { String countAndSayForOneString(String input) { char tmp = input.charAt(0); int num = 1; StringBuffer newString = new StringBuffer(""); for(int k=1;k<input.length();k++) { if(input.charAt(k)==tmp) { num++; continue; } newString.append(Integer.toString(num) + tmp); tmp = input.charAt(k); num = 1; } newString.append(Integer.toString(num) + tmp); return newString.toString(); } public String countAndSay(int n) { String result = "1"; int i = 1; while(i<n) { result = countAndSayForOneString(result); i++; } return result; } }
LeetCode Count and Say 解题报告
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。