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【LeetCode】Find Peak Element (3 solutions)

Find Peak Element

A peak element is an element that is greater than its neighbors.

Given an input array where num[i] ≠ num[i+1], find a peak element and return its index.

You may imagine that num[-1] = num[n] = -∞.

For example, in array [1, 2, 3, 1], 3 is a peak element and your function should return the index number 2.

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Note:

Your solution should be in logarithmic complexity.

 

这题就是求序列最大值。顺序查找或二分查找均可。

满足复杂度要求的话需要用二分查找。

 

解法一:顺序查找

class Solution {public:    int findPeakElement(const vector<int> &num) {        for(int i = 1; i < num.size(); i ++)        {            if(num[i] < num[i-1])            {// <                return i-1;            }        }        return num.size()-1;    }};

 

解法二:二分查找(递归)

class Solution {public:    int findPeakElement(const vector<int> &num) {        return Helper(num, 0, num.size()-1);    }    int Helper(const vector<int> &num, int low, int high)    {        if(low == high)            return low;        else        {            int mid1 = (low+high)/2;            int mid2 = mid1+1;            if(num[mid1] > num[mid2])                return Helper(num, low, mid1);            else                return Helper(num, mid2, high);        }    }};

 

解法三:二分查找(迭代)

class Solution {public:    int findPeakElement(const vector<int> &num)     {        int low = 0;        int high = num.size()-1;                while(low < high)        {            int mid1 = (low+high)/2;            int mid2 = mid1+1;            if(num[mid1] < num[mid2])                low = mid2;            else                high = mid1;        }        return low;    }};

【LeetCode】Find Peak Element (3 solutions)