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Flatten Binary Tree to Linked List
Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1 / 2 5 / \ 3 4 6
The flattened tree should look like:
1 2 3 4 5 6
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: void flatten(TreeNode *root) { TreeNode*now = root; while (now) { if(now->left) { // Find current node‘s prenode that links to current node‘s right subtree TreeNode* pre = now->left; while(pre->right) { pre = pre->right; } pre->right = now->right; // Use current node‘s left subtree to replace its right subtree(original right // subtree is already linked by current node‘s prenode now->right = now->left; now->left = NULL; } now = now->right; } }};
Flatten Binary Tree to Linked List
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