首页 > 代码库 > Compare Version Numbers

Compare Version Numbers

Compare Version Numbers 

Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37
 1 public class Solution { 2     public int compareVersion(String version1, String version2) {         3         String ver1_ch[] = version1.split("\\."); 4         String ver2_ch[] = version2.split("\\."); 5                 6         int i = 0; 7         for(; i < ver1_ch.length && i <ver2_ch.length; i++){ 8              9             if(Integer.valueOf(ver1_ch[i]) > Integer.valueOf(ver2_ch[i]))10                 return 1;11             else if(Integer.valueOf(ver1_ch[i]) < Integer.valueOf(ver2_ch[i]))12                 return -1;13         }14         if(i >= ver1_ch.length && i >= ver2_ch.length)15             return 0;16         else if(i >= ver1_ch.length){17             for(; i < ver2_ch.length; i++){18                 if(Integer.valueOf(ver2_ch[i]) > 0)19                     return -1;20             }21             return 0;22         }23         else24         {25             for(; i < ver1_ch.length; i++){26                 if(Integer.valueOf(ver1_ch[i]) > 0)27                     return 1;28             }29             return 0;30         }31     }32 }

 

Compare Version Numbers