描述we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6R 1P 2G 3r 1p 2g 3

样例输出

191810-17-14-4

 1 import java.util.Scanner; 2  3 public class Main { 4     public static void main(String[] args) { 5         Scanner scanner=new Scanner(System.in); 6         int T; 7         char s[]=new char[1]; 8         int result; 9         int number;10         11         T=scanner.nextInt();12         while(true){13             if(T==0)14                 break;15             T--;16             17             s=scanner.next().toCharArray();18             number=scanner.nextInt();19             20             if(s[0]>=‘a‘ && s[0]<=‘z‘){21                 result=-(s[0]-‘a‘+1)+number;22             }23             else24                 result=(s[0]-‘A‘+1)+number;25             26             System.out.println(result);    27         }28     } 29 }

 

a letter and a number