描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6R 1P 2G 3r 1p 2g 3

样例输出

191810-17-14-4

 1 #include <stdio.h> 2 #include <ctype.h> 3  4 int main(){ 5     int T; 6     char c; 7     int n; 8     int result; 9     10     scanf("%d",&T);11     getchar();12     13     while(T--){14         scanf("%c %d",&c,&n);15         getchar();16         17         if(islower(c)){18             result=-(c-‘a‘+1)+n;19         }20         21         else22             result=c-‘A‘+1+n;23             24         printf("%d\n",result);25     }26     return 0;27 }

 

a letter and a number