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1002. A+B for Polynomials (25) (数学啊 ZJU_PAT)
题目链接:http://www.patest.cn/contests/pat-a-practise/1002
This time, you are supposed to find A+B where A and B are two polynomials.
Input
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.
Output
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input2 1 2.4 0 3.2 2 2 1.5 1 0.5Sample Output
3 2 1.5 1 2.9 0 3.2
代码如下:
#include <cstdio> #include <cstring> double a[1017]; int main() { int k, k1, k2, k3; while(~scanf("%d",&k1)) { memset(a,0,sizeof(a)); int x; double y; int maxx = 0; for(int i = 0; i < k1; i++) { scanf("%d%lf",&x,&y); a[x]+=y; if(x > maxx) maxx = x; } scanf("%d",&k2); for(int i = 0; i < k2; i++) { scanf("%d%lf",&x,&y); a[x]+=y; if(x > maxx) maxx = x; } k = 0; for(int i = 0; i <= maxx; i++) { if(a[i]!=0) k++; } printf("%d",k); for(int i = maxx; i >= 0; i--) { if(a[i] != 0) printf(" %d %.1lf",i,a[i]); } printf("\n"); } return 0; }
1002. A+B for Polynomials (25) (数学啊 ZJU_PAT)