首页 > 代码库 > 【LeetCode】Convert Sorted Array to Binary Search Tree
【LeetCode】Convert Sorted Array to Binary Search Tree
Convert Sorted Array to Binary Search Tree
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
这题思路参照Convert Sorted List to Binary Search Tree,由于vector可以用下标访问,因此不用设置快慢节点,直接访问中间点。
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: TreeNode *sortedArrayToBST(vector<int> &num) { if(num.empty()) return NULL; else return Helper(num, 0, num.size()-1); } TreeNode *Helper(vector<int> &num, int begin, int end) { if(begin > end) return NULL; else { int mid = (begin+end)/2; int midV = num[mid]; TreeNode* root = new TreeNode(midV); root->left = Helper(num, begin, mid-1); root->right = Helper(num, mid+1, end); return root; } }};
【LeetCode】Convert Sorted Array to Binary Search Tree
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。