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Leetcode:Convert Sorted Array to Binary Search Tree
戳我去解题
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
分析:因为BST中序序列是升序的,所以中序遍历序列最中间的元素一定是根节点,然后左右递归构建二叉树
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode *sortedArrayToBST(vector<int> &num) { return addTreeNode(num, 0, num.size() - 1); } TreeNode* addTreeNode(vector<int>& num, int low, int high) { if (low > high) return nullptr; int mid = low + (high - low) / 2; TreeNode* root = new TreeNode(num.at(mid)); root->left = addTreeNode(num, low, mid - 1); root->right = addTreeNode(num, mid + 1, high); return root; } };
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