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Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public TreeNode sortedArrayToBST(int[] num) {
        if(num==null||num.length==0)
            return null;
        return sortedArrayToBST(num,0,num.length-1);
        
        
        
    }

    private TreeNode sortedArrayToBST(int[] num, int start, int end) {
        // TODO Auto-generated method stub
        if(start>end)
            return null;
        int mid = (start+end)/2;
        TreeNode root = new TreeNode(num[mid]);
        root.left=sortedArrayToBST(num,start,mid-1);
        root.right=sortedArrayToBST(num,mid+1,end);
        return root;
    }
}