之前写过一版 shell下解码url，下面给出另外一个版本

function urlencode() {    local LANG=C    for ((i=0;i<${#1};i++)); do        if [[ ${1:$i:1} =~ ^[a-zA-Z0-9\.\~\_\-]$ ]]; then            printf "${1:$i:1}"        else            printf ‘%%%02X‘ "‘${1:$i:1}"        fi    done}urldecode() {    # urldecode <string>    local url_encoded="${1//+/ }"    printf ‘%b‘ "${url_encoded//%/\\x}"}