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HDU 4981
超级水的一道题。上题目
Problem Description
A median in a sequence with the length of n is an element which occupies position number ?n+12? after we sort the elements in the non-decreasing order (the elements are numbered starting with 1). A median of an array (2, 6, 1, 2, 3) is the number 2, and a median of array (0, 96, 17, 23) — the number 17.
An average of a sequence is the sum of sequence divided the size of the sequence.
Goffi likes median very much and he hates average number. So if a sequence‘s average number is larger than or equal to the median of sequence, Goffi will hate the sequence. Otherwise, Goffi will like it.
Now, your are given a sequence. Please find whether Goffi will like it or hate it.
An average of a sequence is the sum of sequence divided the size of the sequence.
Goffi likes median very much and he hates average number. So if a sequence‘s average number is larger than or equal to the median of sequence, Goffi will hate the sequence. Otherwise, Goffi will like it.
Now, your are given a sequence. Please find whether Goffi will like it or hate it.
Input
Input contains multiple test cases (less than 100). For each test case, the first line contains an integern (1≤n≤1000 ), indicating the size of the sequence. Then in the next line, there are n integers a1,a2,…,an (1≤ai≤1000 ), seperated by one space.
Output
For each case, if Goffi like the sequence, output "YES" in a line. Otherwise, output "NO".
Sample Input
5 1 2 3 4 5 4 1 5 6 6
Sample Output
NO YES
让你判断五个数中(N+1)/2的位置这个数是否大于这五个数的平均数。大于就YES,反之NO。(坑点,要将五个数排序。)
上代码
#include <string.h> #include <algorithm> #include <stdio.h> using namespace std; int main() { double a[1050]; int n,i; while(~scanf("%d",&n)) { memset(a,0,sizeof(a)); double sum=0; for(i=1;i<=n;i++) { scanf("%lf",&a[i]); sum+=a[i]; } sum=sum/n; sort(a+1,a+n+1); int mid=(n+1)/2; if(sum<a[mid]) printf("YES\n"); else printf("NO\n"); } return 0; }
HDU 4981
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