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careercup-中等难度 17.7
17.7 给定一个整数，打印该整数的英文描述（例如“One Thousand，Two Hundred Thirty Four”）。
解法：
举个例子，在转换19 323 984时，我们可以考虑分段处理，没三位转换一次，并在适当的地方插入“thousand”（千）和“million”（百万）。也即，
convert（19 323 984）=convert（19）+ “ million ”+convert（323）+“ thousand ”+convert（984）；
C++实现代码：
#include<iostream>#include<string>using namespace std;string digits[10]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};string teens[10]={"Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};string tens[10]={"Ten","Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"};string big[10]={"","Thousand","Million"};string numToString100(int number){ string str; if(number>100) { str+=digits[number/100-1]+" Hundred "; } number%=100; if(number>=11&&number<=19) { return str+teens[number-11]+" "; } else if(number==10||number>=20) { str+=tens[number/10-1]+" "; number%=10; } if(number>=1&&number<=9) { str+=digits[number-1]+" "; } return str;}string numToString(int number){ if(number==0) { return "Zero"; } else if(number<0) { return " Negative "+numToString(-1*number); } int count=0; string str=" "; while(number>0) { if(number%1000) { str=numToString100(number%1000)+big[count]+" "+str; } number/=1000; count++; } return str;}int main(){ cout<<numToString(1109);}
careercup-中等难度 17.7
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