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Balanced Binary Tree 判断平衡二叉树
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
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Tree Depth-first Search/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: int depth(TreeNode *node){ if(node==NULL) return 0; int i=depth(node->left); int j=depth(node->right); return max(i,j)+1; } bool isBalanced(TreeNode *root) { if(root==NULL) return true; int leftDep=depth(root->left); int rightDep=depth(root->right); if(abs(leftDep-rightDep)<=1) return isBalanced(root->left) && isBalanced(root->right); else return false; }};
Balanced Binary Tree 判断平衡二叉树
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