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Balanced Binary Tree 判断平衡二叉树

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

 

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 Tree Depth-first Search
 
/** * Definition for binary tree * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public:    int depth(TreeNode *node){        if(node==NULL)            return 0;        int i=depth(node->left);        int j=depth(node->right);        return max(i,j)+1;    }    bool isBalanced(TreeNode *root) {        if(root==NULL)            return true;        int leftDep=depth(root->left);        int rightDep=depth(root->right);        if(abs(leftDep-rightDep)<=1)            return isBalanced(root->left) && isBalanced(root->right);        else            return false;    }};

 

Balanced Binary Tree 判断平衡二叉树