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LeetCode——Simplify Path
Given an absolute path for a file (Unix-style), simplify it.
For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"
click to show corner cases.
Corner Cases:
- Did you consider the case where path =
"/../"?
In this case, you should return"/". - Another corner case is the path might contain multiple slashes
‘/‘together, such as"/home//foo/".
- In this case, you should ignore redundant slashes and return
"/home/foo".
原题链接：https://oj.leetcode.com/problems/simplify-path/
用一个栈来顺序存储比较方便。
public class SimplifyPath {
public static void main(String[] args) {
String ret = new SimplifyPath().simplifyPath("/a/./b/../../c/");
System.out.println("result:"+ret);
}
public String simplifyPath(String path) {
String[] params = path.split("/");
Stack<String> stack = new Stack<String>();
for(String param : params){
if(param.equals(".."))
stack.pop();
else if(!param.equals("..") && !param.equals(".") && !param.equals(""))
stack.push(param);
}
StringBuilder builder = new StringBuilder();
for(String str :stack)
builder.append("/"+str);
return stack.isEmpty() ? "/":builder.toString();
}
}
LeetCode——Simplify Path
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