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LeetCode 71 Simplify Path
Given an absolute path for a file (Unix-style), simplify it.
For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"
Corner Cases:
- Did you consider the case where path =
"/../"?
In this case, you should return"/". - Another corner case is the path might contain multiple slashes
‘/‘together, such as"/home//foo/".
In this case, you should ignore redundant slashes and return"/home/foo".
思路：简单题，Unix文件的根目录为"/"，"."表示当前目录，".."表示上级目录
public class Solution {
public String simplifyPath(String path) {
String []strs=path.split("/");
StringBuilder sb=new StringBuilder("");
LinkedList<String> ll=new LinkedList<String>();
for(String str:strs){
if(str.equals(".")) continue;
else if(str.equals("..")&&!ll.isEmpty()) {
ll.pollLast();
}else if(str.length()>0&&!str.equals("..")){
ll.add(str);
}
}
if(ll.isEmpty())return "/";
for(String str:ll){
sb.append("/");
sb.append(str);
}
return sb.toString();
}
}LeetCode 71 Simplify Path
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