• Did you consider the case where path = "/../"?
  In this case, you should return "/".
• Another corner case is the path might contain multiple slashes ‘/‘ together, such as "/home//foo/".
  In this case, you should ignore redundant slashes and return "/home/foo".

 1 public class Solution {
 2     public String simplifyPath(String path) {
 3         if (path == null || path.length() == 0 || path.equals("")) {
 4             return "";
 5         }
 6         LinkedList<String> list = new LinkedList<String>();
 7         String[] parts = path.split("/");
 8 
 9         for (int i = 0; i < parts.length; i++) {
10             if (parts[i].equals("") || parts[i].equals(".")) continue;
11             else if (parts[i].equals("..")) {
12                 if (list.isEmpty()) continue;
13                 else {
14                     list.removeLast();
15                 }
16             } else {
17                 list.addLast(parts[i]);
18             }
19         }
20         StringBuilder sb = new StringBuilder();
21         int size = list.size();
22         for (int i = 0; i < size; i++) {
23             sb.append("/");
24             sb.append(list.get(i));
25         }
26         return sb.length() == 0? "/": sb.toString();
27     }
28 }