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71. Simplify Path
https://leetcode.com/problems/simplify-path/#/description
Given an absolute path for a file (Unix-style), simplify it.
For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"
click to show corner cases.
Corner Cases:
- Did you consider the case where path =
"/../"?
In this case, you should return"/". - Another corner case is the path might contain multiple slashes
‘/‘together, such as"/home//foo/".
In this case, you should ignore redundant slashes and return"/home/foo".
Sol :
In Unix, ‘..‘ means parent directory; ‘.‘ means current directory.
Split the path using slash / and check the items. Append addresses and pop parent addresses.
class Solution(object): def simplifyPath(self, path): """ :type path: str :rtype: str """ stack = [] for item in path.split("/"): if item not in [".", "..", ""]: stack.append(item) if item == ".." and stack: stack.pop() return "/" + "/".join(stack)
Note:
1 string/list.split
ex.
string = "www.gziscas.com.cn"
print(string.split(‘.‘))
[‘www‘, ‘gziscas‘, ‘com‘, ‘cn‘]
2 pop()
ex.
aList = [123, ‘xyz‘, ‘zara‘, ‘abc‘];
print "A List : ", aList.pop();
print "B List : ", aList.pop(2);
==>
A List : abc
B List : zara
71. Simplify Path
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