首页 > 代码库 > [LeetCode]Copy List with Random Pointer
[LeetCode]Copy List with Random Pointer
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.
Return a deep copy of the list.
利用hashMap存储,原始的node作为key,new的node作为value,这样就建立了新旧链表的以一一对应关系;/** * Definition for singly-linked list with a random pointer. * class RandomListNode { * int label; * RandomListNode next, random; * RandomListNode(int x) { this.label = x; } * }; */ public class Solution { Map<RandomListNode,RandomListNode> map = new HashMap<>(); public RandomListNode copyRandomList(RandomListNode head) { RandomListNode scan = head; RandomListNode res = new RandomListNode(0); RandomListNode dummy = res; while(scan!=null){ RandomListNode rln = new RandomListNode(scan.label); map.put(scan, rln); dummy.next = rln; scan = scan.next; dummy = dummy.next; } RandomListNode scan2 = head; RandomListNode dummy2 = res.next; while(scan2!=null){ if(scan2.random==null){ dummy2.random = null; }else{ dummy2.random = map.get(scan2.random); } dummy2 = dummy2.next; scan2 = scan2.next; } return res.next; } }
[LeetCode]Copy List with Random Pointer
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。