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Copy List with Random Pointer
类同:剑指 Offer 题目汇总索引第26题
Copy List with Random Pointer
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.
Return a deep copy of the list.
说明：分三步, 1. 每个节点复制其本身并链接在后面。 2， 复制随机指针。 3, 拆分链表。
/** * Definition for singly-linked list with a random pointer. * struct RandomListNode { * int label; * RandomListNode *next, *random; * RandomListNode(int x) : label(x), next(NULL), random(NULL) {} * }; */class Solution {public: RandomListNode *copyRandomList(RandomListNode *head) { if(head == NULL) return NULL; RandomListNode *head2, *p, *p2; p = head2 = head; while(p) { RandomListNode *s = new RandomListNode(p->label); s->next = p->next; p->next = s; p = s->next; } p = head; while(p) { if(p->random) p->next->random = p->random->next; p = p->next->next; } head2 = p2 = head->next; p = head; while(p) { p->next = p->next->next; p = p->next; if(p2->next) { p2->next = p2->next->next; p2 = p2->next; } } return head2; }};
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