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[Leetcode]-Reverse Bits
Reverse bits of a given 32 bits unsigned integer.
将uint数据依照二进制位倒序
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
//思路:将n数据循环左移出。同一时候将移出的数据右移入b中,返回b
uint32_t reverseBits(uint32_t n) {
uint32_t i = 0;
uint32_t t = 1;
uint32_t b = 0;
for(i=0;i<32;i++)
{
if(n & t)
b = (b<<1) | 1;
else
b = b << 1;
n = n>>1;
}
return b;
}
[Leetcode]-Reverse Bits
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