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190. Reverse Bits 反转二进制

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

Follow up:
If this function is called many times, how would you optimize it?

Related problem: Reverse Integer

Credits:
Special thanks to @ts for adding this problem and creating all test cases.


将一个32位整型转成二进制后,反转,再转换回10进制

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class Solution:
    # @param n, an integer
    # @return an integer
    def reverseBits(self, n):
        reBin = ‘{0:b}‘.format(n).zfill(32)[::-1]
        return int(reBin, 2)





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190. Reverse Bits 反转二进制