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[GeeksForGeeks] Longest Bitonic Subsequence
Given an array arr[0.....n-1] containing n positive integers, find the length of the longest bitonic subsequence.
A subsequence of arr[] is called Bitonic if it is first increasing, then decreasing.
Analysis:
This problem is a variation of the standard Longest Increasing Subsequence(LIS) problem. In the standard LIS
problem, we use dynamic programming and create a 1D array lis[i], lis[i] is the length of the longest increasing subsequence
that ends with arr[i].
In this problem, we construct two arrays lis[i] and ids[i] using dynamic programming.
lis[i] stores the length of the longest increasing subsequence ending with arr[i];
lds[i] stores the length of the longest decreasing subsequence starting from arr[i];
Finally, we need to return the max value of lis[i] + lds[i] - 1, where i is from 0 to n - 1.
1 public class Solution { 2 public int longestBitonicSubsequence(int[] arr){ 3 if(arr == null || arr.length == 0){ 4 return 0; 5 } 6 int[] lis = new int[arr.length]; 7 int[] lds = new int[arr.length]; 8 for(int i = 0; i < arr.length; i++){ 9 lis[i] = 1; 10 lds[i] = 1; 11 } 12 for(int i = 0; i < arr.length; i++){ 13 for(int j = 0; j < i; j++){ 14 if(arr[i] > arr[j] && lis[i] < lis[j] + 1){ 15 lis[i] = lis[j] + 1; 16 } 17 } 18 } 19 for(int i = arr.length - 1; i >= 0; i--){ 20 for(int j = arr.length - 1; j > i; j--){ 21 if(arr[i] > arr[j] && lds[i] < lds[j] + 1){ 22 lds[i] = lds[j] + 1; 23 } 24 } 25 } 26 int max = 0; 27 for(int i = 0; i < arr.length; i++){ 28 if(lis[i] + lds[i] - 1 > max){ 29 max = lis[i] + lds[i] - 1; 30 } 31 } 32 return max; 33 } 34 }
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Longest Increasing Subsequence
[GeeksForGeeks] Longest Bitonic Subsequence