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POJ 2533 Longest Ordered Subsequence
Longest Ordered Subsequence
Time Limit: 2000ms
Memory Limit: 65536KB
This problem will be judged on PKU. Original ID: 253364-bit integer IO format: %lld Java class name: Main
A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ..., aN) be any sequence (ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK <= N. For example, sequence (1, 7, 3, 5, 9, 4, 8) has ordered subsequences, e. g., (1, 7), (3, 4, 8) and many others. All longest ordered subsequences are of length 4, e. g., (1, 3, 5, 8).
Your program, when given the numeric sequence, must find the length of its longest ordered subsequence.
Your program, when given the numeric sequence, must find the length of its longest ordered subsequence.
Input
The first line of input file contains the length of sequence N. The second line contains the elements of sequence - N integers in the range from 0 to 10000 each, separated by spaces. 1 <= N <= 1000
Output
Output file must contain a single integer - the length of the longest ordered subsequence of the given sequence.
Sample Input
71 7 3 5 9 4 8
Sample Output
4
Source
Northeastern Europe 2002, Far-Eastern Subregion
解题：LIS
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <cmath> 5 #include <algorithm> 6 #include <climits> 7 #include <vector> 8 #include <queue> 9 #include <cstdlib>10 #include <string>11 #include <set>12 #include <stack>13 #define LL long long14 #define pii pair<int,int>15 #define INF 0x3f3f3f3f16 using namespace std;17 const int maxn = 1010;18 int dp[maxn],d[maxn],n;19 int main() {20 while(~scanf("%d",&n)){21 for(int i = 0; i < n; ++i){22 scanf("%d",d+i);23 dp[i] = INF;24 }25 dp[n] = INF;26 for(int i = 0; i < n; ++i){27 int *p = lower_bound(dp,dp+n+1,d[i]);28 *p = d[i];29 }30 printf("%d\n",lower_bound(dp,dp+n+1,INF)-dp);31 }32 return 0;33 }
POJ 2533 Longest Ordered Subsequence
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