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leetcode----------Pascal's Triangle

题目

Pascal‘s Triangle

通过率30.7%
难度Easy

Given numRows, generate the first numRows of Pascal‘s triangle.

For example, given numRows = 5,
Return

[     [1],    [1,1],   [1,2,1],  [1,3,3,1], [1,4,6,4,1]]

题目的要求是给定行数输出Pascal‘s Triangle,采用集合List进行存储;
首先要搞清楚Pascal‘s Triangle的定义与性质 http://www.mathsisfun.com/pascals-triangle.html
下一层的元素是由上一层元素得到,涉及到相邻两项的求和,特别要注意的是最后的链表的初始化,以及每行元素开头和结尾均为数字1.

java代码:
public class Solution {    public List<List<Integer>> generate(int numRows) {        ArrayList<List<Integer>> result = new ArrayList<List<Integer>>();        if(numRows==0) return result;        ArrayList<Integer> first = new ArrayList<Integer>();        first.add(1);        result.add(first);        for(int n=2;n<=numRows;n++){            ArrayList<Integer> thisRow = new ArrayList<Integer>();             //the first element of a new row is one            thisRow.add(1);            //the middle elements are generated by the values of the previous rows            //A(n+1)[i] = A(n)[i - 1] + A(n)[i]            List<Integer> preRow = result.get(n-2);            for(int i=1;i<n-1;i++){                thisRow.add(preRow.get(i-1)+preRow.get(i));            }            //the last element of a new row is also one            thisRow.add(1);            result.add(thisRow);        }        return result;    }}

 

                                                                  2015.1.10

                                                                    软微1420

leetcode----------Pascal's Triangle