首页 > 代码库 > CDZSC_2015寒假新人(2)——数学 D

CDZSC_2015寒假新人(2)——数学 D

D - D
Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u
Submit Status

Description

There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2). 
 

Input

Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000). 
 

Output

Print the word "yes" if 3 divide evenly into F(n). 

Print the word "no" if not. 
 

Sample Input

012345
 

Sample Output

nonoyesnonono
 

 

 
技术分享
 1 #include<iostream> 2 #include<cstdio> 3 #include<cmath> 4 #include<ctime> 5 using namespace std; 6 int a[1000010]; 7 int main() 8 { 9     a[0]=7;10     a[1]=11;11     for(int i=2;i<1000000;i++)12     {13         a[i]=(a[i-1]+a[i-2])%3;14     }15     int n;16     //printf("%.2f",(double)clock()/CLOCKS_PER_SEC);17     while((scanf("%d",&n))!=EOF)18     {19         if(a[n]%3==0)20         {21         printf("yes\n");22         }23         else24         {25             printf("no\n");26         }27     }28 }
View Code

 

CDZSC_2015寒假新人(2)——数学 D