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Conversions
Problem Description
Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:
Input
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.
Output
For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.
Sample Input
5
1 kg
2 l
7 lb
3.5 g
0 l
Sample Output
1 2.2046 lb
2 0.5284 g
3 3.1752 kg
4 13.2489 l
5 0.0000 g
1 #include <stdio.h> 2 #include <string.h> 3 4 int main(){ 5 int T; 6 double amount; 7 char unit[3]; 8 double total; 9 int time;10 11 time=1;12 13 scanf("%d",&T);14 15 while(T--){16 scanf("%lf%s",&amount,unit);17 18 printf("%d ",time);19 time++;20 21 if(strcmp(unit,"kg")==0){22 total=amount*2.2046;23 24 printf("%.4lf lb\n",total);25 26 }27 28 else if(strcmp(unit,"lb")==0){29 total=amount*0.4536;30 31 printf("%.4lf kg\n",total);32 }33 34 else if(strcmp(unit,"l")==0){35 total=amount*0.2642;36 37 printf("%.4lf g\n",total);38 }39 40 else if(strcmp(unit,"g")==0){41 total=amount*3.7854;42 43 printf("%.4lf l\n",total);44 }45 }46 47 48 return 0;49 }
Conversions
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