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HDU5952 Counting Cliques(暴力)

题意:

100个点1000条边的图,问你有多少个s个点的团,每个节点的度不超过20

思路:

暴力。。边太少,直接纯暴都可以

2106ms

/* ***********************************************
Author        :devil
************************************************ */
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <stack>
#include <map>
#include <string>
#include <time.h>
#include <cmath>
#include <stdlib.h>
#define LL long long
#define rep(i,a,b) for(int i=a;i<=b;i++)
#define dep(i,a,b) for(int i=a;i>=b;i--)
#define ou(a) printf("%d\n",a)
#define pb push_back
#define mkp make_pair
template<class T>inline void rd(T &x)
{
    char c=getchar();
    x=0;
    while(!isdigit(c))c=getchar();
    while(isdigit(c))
    {
        x=x*10+c-0;
        c=getchar();
    }
}
#define IN freopen("in.txt","r",stdin);
#define OUT freopen("out.txt","w",stdout);
using namespace std;
const int inf=0x3f3f3f3f;
const int mod=1e9+7;
const int N=1e2+10;
vector<int>eg[N];
int t,n,m,s,x,y;
int ans,num,tmp[N];
bool mp[N][N];
void dfs(int u,int v)
{
    if(v+eg[u].size()<s) return;
    if(v==s)
    {
        ans++;
        return;
    }
    for(int i=0;i<eg[u].size();i++)
    {
        int j;
        for(j=0;j<num;j++)
            if(!mp[tmp[j]][eg[u][i]])
                break;
        if(j==num)
        {
            tmp[num++]=eg[u][i];
            dfs(eg[u][i],v+1);
            num--;
        }
    }
}
int main()
{
#ifndef ONLINE_JUDGE
IN
#endif
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d%d%d",&n,&m,&s);
        for(int i=1;i<=n;i++) eg[i].clear();
        memset(mp,0,sizeof(mp));
        while(m--)
        {
            scanf("%d%d",&x,&y);
            if(x>y) swap(x,y);
            eg[x].pb(y);
            mp[x][y]=1;
        }
        ans=0;
        n=n-s+1;
        for(int i=1;i<=n;i++)
        {
            num=0;
            tmp[num++]=i;
            dfs(i,1);
        }
        printf("%d\n",ans);
    }
    return 0;
}

 

HDU5952 Counting Cliques(暴力)